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0=-4.9x^2+22.5x+2
We move all terms to the left:
0-(-4.9x^2+22.5x+2)=0
We add all the numbers together, and all the variables
-(-4.9x^2+22.5x+2)=0
We get rid of parentheses
4.9x^2-22.5x-2=0
a = 4.9; b = -22.5; c = -2;
Δ = b2-4ac
Δ = -22.52-4·4.9·(-2)
Δ = 545.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22.5)-\sqrt{545.45}}{2*4.9}=\frac{22.5-\sqrt{545.45}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22.5)+\sqrt{545.45}}{2*4.9}=\frac{22.5+\sqrt{545.45}}{9.8} $
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